Question

$y'=(frac{e^x+pi } sqrt{x}} )'$
Найти первую производную

Answer 1

$y = frac{e^{x}+pi}{sqrt{x}}$

$y' = (frac{e^{x}+pi}{sqrt{x}})' = frac{(e^{x}+pi)'*sqrt{x} - (e^{x}+pi)*sqrt{x}'}{sqrt{x}^2} = \= frac{e^{x}*sqrt{x} - frac{e^{x}+pi}{2sqrt{x}}}{x}$