Question

Сравнить числа 2корень из 7 и 5,(29)

Answer 1

$bfdisplaystyle 2sqrt{7} =sqrt{7cdot2^{2}}=sqrt{7cdot4}=sqrt{28}\\5.(29)=5,2929292929... = sqrt{28.0151004999}\\sqrt{28.0151004999}>sqrt{28}\\5.(29) > 2sqrt{7}$