Question

Решите систему уравнений
{x^2+y^2=4
{x^2-y^2= 0

Answer 1

{x^2+y^2=4  

{x^2-y^2= 0

складываем оба уравнения

x^2 + y^2 + x^2 - y^2 = 4 + 0

2x^2 = 4

x^2 = 2

x₁₂ = +-√2

1. x=√2

2 + y^2 = 4

y² = 2

y₁₂ = +-√2

2. x = - √2

(-√2)² + y^2 = 4

2 + y^2 = 4

y^2 = 2

y₁₂ = +-√2

Ответ (√2, √2) (√2, -√2) (-√2, √2) (-√2, -√2)