Question

−6t2(2t16−3k)+5(4t18−2k)
-6t2- наподобии это 6t в 2 степени

Answer 1

$- 6 {t}^{2} (2 {t}^{16} - 3k) + 5(4 {t}^{18} - 2k) = - 12 {t}^{18} + 18 {t}^{2} k + 20 {t}^{18} - 10k = 8 {t}^{18} + 18 {t}^{2} k - 10k$