Question

2sin квадрат x=корень из 3sin2x

Answer 1

2sin^2(x)=sqrt(3)*sin(2x)

2sin^2(x)=sqrt(3)*2*sin(x)*cos(x)

sin(x)*(sin(x)-sqrt(3)*cos(x))=0

1)  sin(x)=0

x=pi*n

 

2) sin(x)-sqrt(3)*cos(x)=0

sin(x)=sqrt(3)*cos(x)

sin(x)/cos(x)=sqrt(3)

tg(x)=sqrt(3)

x=arctg(sqrt(3)+pi*n

x=pi/3+pi/n