Question

знайти похідну функції f(x)=x^2+1/x-2
$f(x)=\frac{x^{2}+1 }{x-2}$

Answer 1

Ответ:

$f(x) = \frac{ {x}^{2} + 1}{x - 2}$

$f'(x) = \frac{( {x}^{2} + 1)'(x - 2) - (x - 2)'( {x}^{2} + 1)}{ {(x - 2)}^{2} } = \\ = \frac{2x(x - 2) - ( {x}^{2} + 1)}{{( {x}^{} - 2) {}^{2} } } = \frac{2 {x}^{2} - 4x - {x}^{2} - 1 }{ {(x - 2)}^{2} } = \\ = \frac{ {x}^{2} - 4x - 1}{ {(x - 2)}^{2} }$