Question

Знайти область визначення функції у=√х+4 + 8/х²-9​

Answer 1

$\displaystyle\bf\\y=\sqrt{x+4} +\frac{8}{x^{2} -9} \\\\\\\left \{ {{x+4\geq 0} \atop {x^{2} -9\neq 0}} \right. \\\\\\\left \{ {{x+4\geq 0} \atop {(x -3)(x+3)\neq 0}} \right. \\\\\\\left\{\begin{array}{ccc}x\geq -4\\x-3\neq 0\\x+3\neq 0\end{array}\right \\\\\\\left\{\begin{array}{ccc}x\geq -4\\x\neq 3\\x\neq -3\end{array}\right \\\\\\Otvet \ : \ D(y)=\Big[-4 \ ; \ -3\Big)\cup\Big(-3 \ ; \ 3\Big)\cup\Big(3 \ ; \ +\infty\Big)$