Question

значение производной функции

Answer 1

$y=sqrt[3]{(x-3)^{4} } -frac{3}{2x^{3} -3x+1}=(x-3)^{frac{4}{3} }-frac{3}{2x^{3}-3x+1 }\\y'=frac{4}{3}(x-3)^{frac{1}{3} }*(x-3)'-frac{3'*(2x^{3}-3x+1)-3*(2x^{3}-3x+1)'}{(2x^{3} -3x+1)^{2} }=frac{4sqrt[3]{x-3} }{3}-frac{-3*(6x^{2}-3) }{(2x^{3}-3x+1)^{2}}=frac{4sqrt[3]{x-3} }{3}+frac{9(2x^{2}-1) }{(2x^{3}-3x+1)^{2}}$