Question

.... Задание прикреплено....

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

$2)frac{1+tg^{2}(-frac{pi }{6})}{1+Ctg^{2}(-frac{pi }{6})}=frac{1+tg^{2}frac{pi }{6}}{1+Ctg^{2}frac{pi }{6}}= frac{frac{1}{Cos^{2}frac{pi }{6}}}{frac{1}{Sin^{2}frac{pi }{6}} }=frac{Sin^{2}frac{pi }{6}}{Cos^{2}frac{pi }{6}}=tg^{2}frac{pi }{6}=(frac{1}{sqrt{3}} )^{2}=frac{1}{3}$

$4)frac{3-Sin^{2}(-frac{pi }{3})-Cos^{2}(-frac{pi }{3})}{2Cos(-frac{pi }{4}) }=frac{3-(Sin^{2}frac{pi }{3}+Cos^{2}frac{pi }{3})}{2Cosfrac{pi }{4} }=frac{3-1}{2*frac{sqrt{2} }{2} } =frac{2}{sqrt{2} }=sqrt{2}$

$2)Cosalpha-Ctgalpha*Sin(-alpha)=Cosalpha+frac{Cosalpha }{Sinalpha}*Sinalpha =Cosalpha +Cosalpha=2Cosalpha\\4)tg(-alpha )*Ctg(-alpha)+Cos^{2}(-alpha)+Sin^{2}alpha =tgalpha*Ctgalpha+(Cos^{2}alpha+Sin^{2}alpha)=1+1=2$

Answer 3

Помоги пожалуйста https://znanija.com/task/31970700

Answer 4

Помогла