Question

Z1=-2+3i;Z2=4-i ;Z3=4+4i .Найти Z1+Z2+z3, Z1*Z3*Z2, z1/z2-Z3

Answer 1

z1 = -2 + 3i; z2 = 4 - i; z3 = 4 + 4i

1) z1 + z2 + z3 = -2 + 3i + 4 - i + 4 + 4i = (-2+4+4) + (3i-i+4i) = 6 + 6i

2) z1*z3*z2 = (-2+3i)(4+4i)(4-i) = (-8+12i-8i+12i^2)(4-i) = (-20+4i)(4-i) =

= -80 + 16i + 20i - 4i^2 = -76 + 36i

3) $frac{z1}{z2}-z3=frac{-2+3i}{4-i}-(4+4i)=frac{(-2+3i)(4+i)}{(4-i)(4+i)} -(4+4i)=$

$=frac{-8+12i-2i+3i^2}{16-i^2} -(4+4i) =frac{-11+10i}{17}-(4+4i)=frac{-11+10i}{17}-frac{68+68i}{17}=$

$=frac{-11+10i}{17}-frac{68+68i}{17}=frac{-11+10i-68-68i}{17}=frac{-79-58i}{17}=-frac{79}{17} -frac{58i}{17}$

Answer 2

https://znanija.com/task/29548591

Answer 3

помогмте еще это решить