Question

y = x^4-5x^2+4 найти нули функции

Answer 1

$x^{4}-5 x^{2}+4=0 \ x^{2} =t \ t^{2} -5t+4=0 \ D= b^{2}-4ac= 25- 4*1*4=9 \ [tex] \ x_{1}= frac{-b+ sqrt{D} }{2a}= frac{5+3}{2*1}=4 \ x_{2}= frac{-b- sqrt{D} }{2a}= frac{5-3}{2*1}=1 \ 1) x^{2} =t \ x^{2} = 4 \ x=+и-2 \ 2) x^{2} =1 \ x= + и -1$