Question

y=log3(x^2+24x) помогите срочно

Answer 1

$y=log_3(x^2+24x)\\OOF:; ; ; x^2+24x>0\\x(x+24)geq 0\\Metod; intervalov:\\x_1=0; ,; ; x+24=0; ,; ; x_2=-24\\+++(-24)---(0)+++\\xin (-infty ,-24)cup (0,+infty )$