Question

x2 - 6x + 8 = 0;
3y2 – 8y + 4 = 0; помогитеее

Answer 1

х² - 6х + 8 = 0

D = (-6)² - 4×8 = 4 = 2²

х1 = (6+2)/2 = 4, х2 = (6-2)/2 = 2

3у² - 8у + 4 = 0

D = (-8)² - 4×4×3 = 16 = 4²

х1 = (8+4)/2×3 = 2, х² = (8-4)/2×3 = 2/3