Question

{x=y-2 x²+y²=4 решить алгебраидным способом

Answer 1

x=y-2

x^2+y^2=4

y^2-4y+4+y^2=4

2y^2-4y=0

2y(y-2)=0

y1=0

y2=2

x1=-2

x2=0

Answer 2

$left { {{x=y-2} atop {x^{2}+y^{2}}=4} right.\\left { {{x=y-2} atop {(y-2)^{2}+y^{2}}=4} right.\\left { {{x=y-2} atop {y^{2}-4y+4+y^{2}}=4} right\\left { {{2y^{2}-4y=0}atop {x=y-2}} right.\\left { {{y^{2}-2y=0}atop {x=y-2}} right.\\left { {{y(y-2)=0} atop {x=y-2}} right.\\left { {y_{1} =0} atop {x_{1}=- 2}} right.\\left { {{y_{2}= 2} atop {x_{2}= 0}} right.$

Ответ : (- 2 ; 0) , (0 ; 2)