Question

x³²-(x-1)*(x+1)*(x²+1)*(x⁴+1)*(x⁸+1)*(x¹⁶+1)  упростить выражение 

Answer 1

$x^{32}-(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)(x^{16}+1)=\\=x^{32}-(x^2-1)(x^2+1)(x^4+1)(x^8+1)(x^{16}+1)=\\=x^{32}-(x^4-1)(x^4+1)(x^8+1)(x^{16}+1)=\\=x^{32}-(x^8-1)(x^8+1)(x^{16}+1)=\\=x^{32}-(x^{16}-1)(x^{16}+1)=\\=x^{32}-(x^{32}-1)=x^{32}-x^{32}+1=1$

Answer 2

Супер!

Answer 3

)))))