Question

x/x+1 - 1/x ＝ 1/x^2+x Решите уравнение​

Answer 1

$frac{x}{x+1}-frac{1}{x}=frac{1}{x^{2}+x}\\frac{x}{x+1}-frac{1}{x}-frac{1}{x(x+1)}=0\\frac{x^{2}-x-1-1 }{x(x+1)}=0\\frac{x^{2}-x-2 }{x(x+1)}=0\\frac{(x-2)(x+1)}{x(x+1)}=0\\left { {{(x-2)(x+1)=0} atop {xneq0;xneq-1  }} right.\\x-2=0\\x=2$

Ответ : 2