Question

x²+3x√2+4=0 как решить ?

Answer 1

$x^2+3sqrt{2}x+4=0  \ D=(3*sqrt{2})^2-4*4*1=9*2-16=18-16 = 2 \ x_{1,2} = frac{-3sqrt{2}бsqrt{2}}{2} \ x_1 = frac{-3sqrt{2}-sqrt{2}}{2} = frac{-4sqrt{2}}{2} = -2sqrt{2} \ x_2 = frac{-3sqrt{2}+sqrt{2}}{2}= frac{-2sqrt{2}}{2} = -sqrt{2}$