Question

x²-3x+2=0.
x²-4x+3=0.
x²-5x+4=0

Answer 1

$x^2-3x+2=0,\(D=9-8=1,)\x=frac{3pm1}{2},\x_1=2,\x_2=1.$

$x^2-4x+3=0,\(D=16-12=4,)\x=frac{4pm2}{2} ,\x_1=3,\x_2=1.$

$x^2-5x+4=0,\(D=25-16=9,)\x=frac{5pm3}{2},\ x_1=4,\x_2=1.$