Question

(x + 3)^2 - 2(x+3) - 8 = 0

Answer 1

Ответ:

${(x + 3)}^{2} - 2 \times (x + 3) - 8 = 0 \\ {(x + 3)}^{2} - 2x - 6 - 8 = 0 \\ x \times x + 6x + 9 - 2x - 6 - 8 = 0 \\ {x}^{2} + 4x - 5 = 0 \\ {x}^{2} + 4x - x - 5= 0 \\ x \times (x + 5) - (x + 5) = 0 \\ x + 5 = 0 \\ x - 1 = 0 \\ x = - 5 \\ x = 1$

Answer 2

Ответ:

1 и -5

Пошаговое объяснение:

(x + 3)^2 - 2(x+3) - 8 = 0

х²+6х+9-2х-6-8=0

х²+4х-5=0

По теореме Виета х=1 и  х=-5