Question

x=2-y
y^2+x=32
помогите решить

Answer 1

$left { {{x=2-y} atop {y^{2}+x= 3^{2} }} right. left { {{x=2-y} atop { (2-y)^{2}+2-y=9 }} right.* *(2-y)^{2} +2-y=9 4+4y- y^{2} +2-y=9 -y^{2} +4y-3=0 y^{2} - 4y+3=0 y_{1} =1 y_{2} =3* left { {{ x_{1} =2-y} atop { y_{1}=1 }} right. left { {{ x_{1}= 1 } atop { y_{1}=1}} right. left { {{ x_{2=2-y} } atop {y_{2=3} left { {{ x_{2}=-1 } atop { y_{2}=3 }} right. .$

Answer 2

ответ (1;1), (-1;3)