Question

x^2=x^3+2x^4
21 задание огэ.
квадратное неравенство​

Answer 1

${x}^{2} = {x}^{3} + 2x^{4}$

${x}^{2} - {x}^{3} - 2 {x}^{4} = 0$

${x}^{2} times (1 - x - 2 {x}^{2} ) = 0$

${x}^{2} times ( - 2 {x}^{2} - x + 1) = 0$

${x}^{2} times ( - 2 {x}^{2} + x - 2x + 1) = 0$

${x}^{2} times ( - (2x - 1) times (x + 1)) = 0$

$- {x}^{2} times (2x - 1) times (x + 1) = 0$

$- {x}^{2} = 0 : : : : : : 2x - 1 = 0 : : : : : : x + 1 = 0$

$x = 0 : : : : : : x = frac{1}{2} : : : : : : x = - 1$