Question

(x^2+x-1)(x^2+x+2)=40 Пожалуйста помогите !

Answer 1

$(x^2+x-1)(x^2+x+2)=40, \ x^2+x-1=a, \ x^2+x+2=x^2+x-1+3=a+3, \ a(a+3)=40, \ a^2+3a-40=0, \ a_1=-8, a_2=5, \ left [ {{x^2+x-1=-8,} atop {x^2+x-1=5;}} right. \ x^2+x+7=0, \ D=-27<0, \ xinvarnothing, \ x^2+x-6=0, \ x_1=-3, x_2=2.$