Question

x^2-9/x^2-6x+9 pomogite mne

Answer 1

$frac{x^2-9}{x^2-6x+9}=frac{x^2-3^2}{x^2-2*x*3+3^2}=\\frac{(x-3)(x+3)}{(x-3)^2}=frac{x+3}{x-3}$