Question

(x^2-6x)^2+14(x-3)^2=81

Answer 1

$(x^2-6x)^2+14(x-3)^2=81\ (x^2-6x)^2+14(x-3)^2-81=0\ (x^2-6x)^2+14(x^2-6x+9)-81=0\ zamena\ x^2-6x=t\ t^2+14t+14*9-81=0\ t^2+14t+45=0\ (t+5)(t+9)=0\ t=-5;-9\\ x^2-6x=-5\ x^2-6x+5=0\ D=36-4*1*5=4^2\ x_{1}=frac{6+4}{2}=5\ x_{2}=frac{6-4}{2}=1\\ x^2-6x+9=0\ (x-3)^2=0\ x=3$

Ответ  1;3;5

Answer 2

спасибо огромное!