Question

((x^2-6)/x)^2 -5=4*((x^2-6)/x)

Answer 1

Ответ:

$x_{1} =7\x_{2.4} =-2\x_{3}=3$

Объяснение:

$(frac{x^{2} -6}{x} )^{2} -5 = 4* frac{x^{2} -6}{x}\(frac{x^{2} -6}{x})^{2} -4*frac{x^{2} -6}{x}-5=0\frac{x^{2} -6}{x} = z\z^{2} -4z-5=0\sqrt{D} = sqrt{(-4)^{2} -4*1*(5)} = sqrt{16+20} =sqrt{36} = 6\ z_{1}= frac{4+6}{2} = 5\z_{2} = frac{4-6}{2} = -1\1) frac{x^{2} -6}{x} = 5\x^{2} -6=5x\x^{2} -5x-6=0\sqrt{D} =sqrt{ (-5)^{2} - 4*1*(-6) } = sqrt{25+24}=sqrt{49} = 9\x_{1} = frac{5+9}{2*1} = 7\x_{2} =frac{5-9}{2} = -2\2) frac{x^{2} -6}{x} =-1\x^{2} -6 = -x$$x^{2} +x-6=0\sqrt{D}=sqrt{1^{2}-4*1*(-6) } = sqrt{25} =5\x_{3} =frac{1+5}{2}=3\x_{4} =frac{1-5}{2} =-2$