Question

(X^2+4x+9)(x^2+4x+3)=-5

Answer 1

$(x^2+4x+9)(x^2+4x+3)=-5 \ x^4+4x^3+3x^2+4x^3+16x^2+12x+9x^2+36x+27+5 =0\ x^4+8x^3+28x^2+48x+32-0 \ (x-2)^2(x^2+4x+8) = 0 \ x=-2$