Выразите число через синус или косинус положительного угла,не превышающего П/4
1)Sin П/3
2)Cos П/3
3)Sin 5П/7
4)Cos 11П/13
5)Sin 13П/5
6)Cos 14П/5
7)Cos 29П/7
8)Sin 24П/7
Ответы на вопрос
Ответил fasalv
0
1) ![sin(pi/3)=cos(pi/2-pi/3)=cos(pi/6)\
2) cos(pi/3)=sin(pi/2-pi/3)=sin(pi/6)\
3) sin(5pi/7)=cos(pi/2-5pi/7)=cos(-3pi/14)=cos(3pi/14)\
4) cos(11pi/13)=-cos(pi-11pi/13)=-cos(2pi/13)\
5)sin(13pi/5)=sin(2pi+3pi/5)=cos(pi/2-3pi/5)=cos(-pi/10)=\=cos(pi/10)\
6)cos(14pi/5)=cos(2pi+4pi/5)=-cos(pi-4pi/5)=-cos(pi/5)\
7) cos(29pi/7)=cos(2pi+2pi+pi/7)=cos(pi/7)\
8)sin(24pi/7)=sin(2pi+2pi-4pi/7)=sin(-4pi/7)=-sin(4pi/7)=\=-cos(pi/2-4pi/7)=-cos(-pi/14)=-cos(pi/14)](https://tex.z-dn.net/?f=sin%28pi%2F3%29%3Dcos%28pi%2F2-pi%2F3%29%3Dcos%28pi%2F6%29%5C%0A2%29+cos%28pi%2F3%29%3Dsin%28pi%2F2-pi%2F3%29%3Dsin%28pi%2F6%29%5C%0A3%29+sin%285pi%2F7%29%3Dcos%28pi%2F2-5pi%2F7%29%3Dcos%28-3pi%2F14%29%3Dcos%283pi%2F14%29%5C%0A4%29+cos%2811pi%2F13%29%3D-cos%28pi-11pi%2F13%29%3D-cos%282pi%2F13%29%5C%0A5%29sin%2813pi%2F5%29%3Dsin%282pi%2B3pi%2F5%29%3Dcos%28pi%2F2-3pi%2F5%29%3Dcos%28-pi%2F10%29%3D%5C%3Dcos%28pi%2F10%29%5C%0A6%29cos%2814pi%2F5%29%3Dcos%282pi%2B4pi%2F5%29%3D-cos%28pi-4pi%2F5%29%3D-cos%28pi%2F5%29%5C%0A7%29+cos%2829pi%2F7%29%3Dcos%282pi%2B2pi%2Bpi%2F7%29%3Dcos%28pi%2F7%29%5C%0A8%29sin%2824pi%2F7%29%3Dsin%282pi%2B2pi-4pi%2F7%29%3Dsin%28-4pi%2F7%29%3D-sin%284pi%2F7%29%3D%5C%3D-cos%28pi%2F2-4pi%2F7%29%3D-cos%28-pi%2F14%29%3D-cos%28pi%2F14%29 "sin(pi/3)=cos(pi/2-pi/3)=cos(pi/6)\
2) cos(pi/3)=sin(pi/2-pi/3)=sin(pi/6)\
3) sin(5pi/7)=cos(pi/2-5pi/7)=cos(-3pi/14)=cos(3pi/14)\
4) cos(11pi/13)=-cos(pi-11pi/13)=-cos(2pi/13)\
5)sin(13pi/5)=sin(2pi+3pi/5)=cos(pi/2-3pi/5)=cos(-pi/10)=\=cos(pi/10)\
6)cos(14pi/5)=cos(2pi+4pi/5)=-cos(pi-4pi/5)=-cos(pi/5)\
7) cos(29pi/7)=cos(2pi+2pi+pi/7)=cos(pi/7)\
8)sin(24pi/7)=sin(2pi+2pi-4pi/7)=sin(-4pi/7)=-sin(4pi/7)=\=-cos(pi/2-4pi/7)=-cos(-pi/14)=-cos(pi/14)")
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