Question

Выполните вычитание дробей:​

Answer 1

$\frac{2-3y}{y^{2}-9 }-\frac{5-2y}{3-y} =\frac{2-3y}{(y-3)(y+3)} +\frac{5-2y}{y-3}=\frac{2-3y+(5-2y)(y+3)}{(y-3)(y+3)} =\frac{2-3y+5y+15-2y^{2}-6y }{(y-3)(y+3)}=\\\\=\frac{-2y^{2}-4y+17 }{(y-3)(y+3)}= -\frac{2y^{2}+4y-17 }{y^{2}-9 }=\boxed{\frac{2y^{2}+4y-17 }{9-y^{2} }}$