Question

Выполнить задания 1,3,9

Answer 1

Ответ:

Пошаговое объяснение:

№1

$4\frac{5}{9}+7\frac{1}{6}=\frac{41}{9}+\frac{43}{6}=\frac{41\cdot3+43\cdot2}{18}=\frac{209}{18}=11\frac{11}{18}$

$6\frac{11}{12}+8\frac{13}{18}=\frac{83}{12}+\frac{157}{18}=\frac{83\cdot3+157\cdot2}{36}=\frac{563}{36}=15\frac{23}{36}$

$2\frac{3}{16}+1\frac{7}{24}+3\frac{1}{12}=\frac{35}{16}+\frac{31}{24}+\frac{37}{12}=\frac{35\cdot3+31\cdot2+37\cdot4}{48}=\frac{315}{48}=6\frac{27}{48}=6\frac{9}{16}$

№3

$8\frac{9}{14}-3\frac{3}{7}=\frac{121}{14}-\frac{24}{7}=\frac{73}{14}=5\frac{3}{14}$

$7\frac{5}{12}-3\frac{7}{24}=\frac{89}{12}-\frac{79}{24}=\frac{99}{24}=4\frac{1}{8}$

$12\frac{11}{12}-5\frac{13}{18}=\frac{155}{12}-\frac{103}{18}=\frac{155\cdot3-103\cdot2}{36}=\frac{259}{36}=7\frac{7}{36}$

№9

$x=10\frac{6}{7}-6\frac{3}{11}=\frac{76}{7}-\frac{69}{11}=\frac{76\cdot11-69\cdot7}{77}=\frac{353}{77}=4\frac{45}{77}$

$x=9\frac{5}{36}-2\frac{4}{9}=\frac{329}{36}-\frac{22}{9}=\frac{241}{36}=15\frac{1}{36}$

$x=7\frac{9}{20}+5\frac{17}{60}=\frac{149}{20}+\frac{317}{60}=\frac{764}{60}=12\frac{54}{60}=12\frac{9}{10}$