Question

Вычислите:
$\lim_{x \to \ 0} \frac{(1+ x^{3} )^{3}-(3x+1) }{x+ x^{5} }$

Answer 1

(1+3x^3-1-3x+3x^6+x^9)/x(1+x^4)=(3x^3+x^9+3x^6-3x)/x(1+x^4)=(x^8+3x^5+3x^2-3)/(1+x^4)
x->0
(0+3*0+3*0-3)/(1+0)=-3
ответ -3