Question

Вычислите массовую долю фосфора в следующих соединениях: PH³, P²O⁵, P²O³​

Answer 1

PH3

W% P = 31 / 34 * 100% = 91,1%

P2O5

W% P = 62 / 142 * 100% = 43,6%

P2O3

W% P = 62 / 110 * 100% = 56,3%

Answer 2

Ответ:

Mr[PH3] = Ar[H] * 3 + Ar[P] = 1 * 3 + 31 = 34

ω (H) = 3 : 34 * 100 = 9 % = 0.09

ω (P) = 31 : 34 * 100 = 91 % = 0.91

Mr[P2O5] = Ar[P] * 2 + Ar[O] * 5 = 31 * 2 + 16 * 5 = 142

ω (P) = 62 : 142 * 100 = 44 % = 0.44

ω (O) = 80 : 142 * 100 = 56 % = 0.56

Mr[P2O3] = Ar[P] * 2 + Ar[O] * 3 = 31 * 2 + 16 * 3 = 110

ω (P) = 62 : 110 * 100 = 56 % = 0.56

ω (O) = 48 : 110 * 100 = 44 % = 0.44

Объяснение: