Вычислите: log2 56 - log2 7 + 16^log2 3
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Ответил IamHindiChunk
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= log2 56 - log2 7 + 2^4log2 3 = log2 56 - log2 7 + 2^log2 3^4
= log2 56 - log2 7 + 2^log2 81 = log2 56 - log2 7 + 81
= log2 (56/7) + 81 = log2 8 + 81 = 3 + 81 = 84
= log2 56 - log2 7 + 2^log2 81 = log2 56 - log2 7 + 81
= log2 (56/7) + 81 = log2 8 + 81 = 3 + 81 = 84
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