Question

Вычислите интеграл !

Answer 1

Ответ:

$\displaystyle \int \dfrac{dx}{\sqrt[3]{7x-9}}=\int (7x-9)^{-\frac{1}{3}}\, dx=\dfrac{1}{7}\cdot \dfrac{(7x-9)^{\frac{2}{3}}}{\dfrac{2}{3}}+C=\dfrac{3\sqrt[3]{(7x-9)^2}}{14}+C\\\\\\\\\star \ \ \int (kx+b)^{n}\, dx=\dfrac{1}{k}\cdot \dfrac{(kx+b)^{n+1}}{n+1}+C\ \ \ \star$