Question

Вычислите.и если можно подробней.

Answer 1

$sqrt{(sqrt{3}-1)^2*2(2+sqrt{3})} =sqrt{(3-2sqrt{3}+1)*2(2+sqrt{3}) } =\sqrt{(4-2sqrt{3})*2(2+sqrt{3})} =sqrt{(8-4sqrt{3})(2+sqrt{3}) } =\sqrt{16+8sqrt{3} -8sqrt{4}-12 }=sqrt{4}=2\\\ sqrt{(sqrt{5}+1)^2*2(3-sqrt{5})} =sqrt{(5+2sqrt{5}+1)*2(3-sqrt{5})}=\ sqrt{(6+2sqrt{5})*2(3-sqrt{5})}=sqrt{(12+4sqrt{5})(3-sqrt{5})}=\sqrt{36-12sqrt{5}+12sqrt{5}-20}=sqrt{16}=4$