Question

вычислить log 2 64- 2log2 4+ log2 32

Answer 1

log(2) 64 - log(2) 4^2 + log(2) 32 = 64/16 * 32 = 4*32= 128

Answer 2

$log_2 64-2log_2 4+log_2 32=log_2 2^6-2log_2 2^2+log_2 2^5=\ 6-2cdot2+5=7$