Вычислить (2a+c)(a-b), если a={4,-2,3} b={1,-2,0} c={2,1,-3}
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Ответил Regent1828
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(2a + c)(a - b)
1) a = 4; b = 1; c = 2 (2a+c)(a-b) = (8+2)(4-1) = 10*3 = 30
2) a = -2; b = -2; c = 1 (2a+c)(a-b) = (-4+1)(-2+2) = -3*0 = 0
3) a = 3; b = 0; c = -3 (2a+c)(a-b) = (6-3)(3-0) = 3*3 = 9
1) a = 4; b = 1; c = 2 (2a+c)(a-b) = (8+2)(4-1) = 10*3 = 30
2) a = -2; b = -2; c = 1 (2a+c)(a-b) = (-4+1)(-2+2) = -3*0 = 0
3) a = 3; b = 0; c = -3 (2a+c)(a-b) = (6-3)(3-0) = 3*3 = 9
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