Question

вычисление и найти значение выражения

Answer 1

$64^{ \frac{2}{3} }- \frac{25^{0.5}}{(0.0016)^{0.25}} +(1.25)^0=4^2- \frac{5}{0.2} +1=16-25+1=-8 \\ \\ \\ \frac{b^{1.5}}{b^{0.5}+2}+ \frac{2b^{1.5}-16}{b-4} =\frac{b^{1.5}(b^{0.5}-2)}{(b^{0.5}+2)(b^{0.5}-2)}+ \frac{2b^{1.5}-16}{(b^{0.5}+2)(b^{0.5}-2)} = \\ \\ =\frac{b^{2}-2b^{1.5}+2b^{1.5}-16}{(b^{0.5}+2)(b^{0.5}-2)}=\frac{b^{2}-16}{b-4}=\frac{(b+4)(b-4)}{b-4}= b+4 \\ \\ b+4=29+4=33$