Question

Все, кроме а), пожалуйста

Answer 1

б) x₁ * x₂³ + x₂ * x₁³ = x₁x₂(x₁² + x₂²)

x₁ * x₂ = 8           x₁ + x₂ = 6

x₁² + x₂² = (x₁ + x₂)² - 2x₁ * x₂ = 6² - 2 * 8 = 36 - 16 = 20

x₁ * x₂³ + x₂ * x₁³ = x₁ * x₂(x₁² + x₂²) = 8 * 20 = 160

в)

$frac{x_{1} }{x_{2} }+frac{x_{2} }{x_{1} }=frac{x_{1}^{2}+x_{2}^{2}}{x_{1}*x_{2}}=frac{20}{8}=2,5$

г)

x₁⁴ + x₂⁴ = (x₁² + x₂²)² - 2x₁²x₂² = [(x₁ + x₂)² - 2x₁x₂]² - 2(x₁x₂)² = (36 - 2 * 8)²- 2 * 8²=

= 20² - 2 * 64 = 400 - 128 = 272