Question

Внести множник під знак кореня
6 √а
-0,3 √10

Answer 1

$\displaystyle \it6 \sqrt{a} = \sqrt{ {6}^{2} \cdot a} = \boxed{ \huge \bf\sqrt{36a} }; \\ \it - 0.3 \sqrt{10} = - 1 \cdot0.3 \sqrt{10} = - \sqrt{ {0.3}^{2} \cdot10} = - \sqrt{0.09 \cdot10} = \boxed{ \huge \bf- \sqrt{0.9} }.$