Question

Упростите выражения.Помогите плиз​

Answer 1

$\frac{2}{3}x \times - \frac{1}{6} x+ \frac{8}{9}x = \frac{2x}{3} - \frac{x}{6} + \frac{8x}{9} = \frac{6 \times 2x}{6 \times 3} - \frac{3x}{3 \times 6} + \frac{2 \times 8x}{2 \times 9} = \frac{12x}{18} - \frac{3x}{18} + \frac{16x}{18} = \frac{12x - 3x + 16x}{18} = \frac{25x}{18} = \frac{25}{18} x$

$- \frac{15}{16} y + \frac{3}{8} y - \frac{1}{4} y = - \frac{15y}{16} + \frac{3y}{8} - \frac{y}{4} = - \frac{15y}{16} + \frac{2 \times 3y}{2 \times 8} - \frac{4y}{4 \times 4} = - \frac{15y}{16} + \frac{6y}{16} - \frac{4y}{16} = \frac{ - 15y + 6y - 4y}{16} = \frac{ - 13y}{16} = - \frac{13}{16}y$

$\frac{23}{24} z - \frac{5}{8}z - \frac{7}{12}z = \frac{23z}{24} - \frac{5z}{8} - \frac{7z}{12} = \frac{23z}{24} - \frac{3 \times 5z}{3 \times 8} - \frac{2 \times 7z}{2 \times 12} = \frac{23z}{24} - \frac{15z}{24} - \frac{14z}{24} = \frac{23z - 15z - 14z}{24} = \frac{ - 6z}{24} = - \frac{z}{4} = - \frac{1}{4} z$

$8 \frac{1}{15} a + 3 \frac{2}{3} a - 20 \frac{4}{5} a = \frac{121}{15}a + \frac{11}{3} a - \frac{104}{5} a = - \frac{136}{15} a$