упростите выражение a^-3,5*(4a^3)^0,3
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Ответил VANILLY
0
a^-3,5*(4a^3)^0,3 = а^-3.5*4^0.3*а^0.9 = 4^0.3*а^-2.6 = 4^3/10*а^-13/5=
=![{4}^{ frac{3}{10} } times frac{1}{{a}^{ frac{13}{5} } } = frac{ {4}^{ frac{3}{10} } }{ {a}^{ frac{13}{5} } } = frac{({2^{2} )}^{ frac{3}{10} } }{ sqrt[5]{ {a}^{13} } } = \ \ = frac{ {2}^{ frac{3}{5} } }{ {a}^{2} sqrt[5]{ {a}^{ 3} } } = frac{ sqrt[5]{ {2}^{3} } }{ {a}^{2} sqrt[5]{ {a}^{3} } } = frac{ sqrt[5]{8} }{ {a}^{2} sqrt[5]{ {a}^{3} } }](https://tex.z-dn.net/?f=+%7B4%7D%5E%7B+frac%7B3%7D%7B10%7D+%7D+times+frac%7B1%7D%7B%7Ba%7D%5E%7B+frac%7B13%7D%7B5%7D+%7D+%7D+%3D+frac%7B+%7B4%7D%5E%7B+frac%7B3%7D%7B10%7D+%7D+%7D%7B+%7Ba%7D%5E%7B+frac%7B13%7D%7B5%7D+%7D+%7D+%3D+frac%7B%28%7B2%5E%7B2%7D+%29%7D%5E%7B+frac%7B3%7D%7B10%7D+%7D+%7D%7B+sqrt%5B5%5D%7B+%7Ba%7D%5E%7B13%7D+%7D+%7D+%3D+%5C+%5C+%3D+frac%7B+%7B2%7D%5E%7B+frac%7B3%7D%7B5%7D+%7D+%7D%7B+%7Ba%7D%5E%7B2%7D+sqrt%5B5%5D%7B+%7Ba%7D%5E%7B+3%7D+%7D+%7D+%3D+frac%7B+sqrt%5B5%5D%7B+%7B2%7D%5E%7B3%7D+%7D+%7D%7B+%7Ba%7D%5E%7B2%7D+sqrt%5B5%5D%7B+%7Ba%7D%5E%7B3%7D+%7D+%7D+%3D+frac%7B+sqrt%5B5%5D%7B8%7D+%7D%7B+%7Ba%7D%5E%7B2%7D+sqrt%5B5%5D%7B+%7Ba%7D%5E%7B3%7D+%7D+%7D+ "{4}^{ frac{3}{10} } times frac{1}{{a}^{ frac{13}{5} } } = frac{ {4}^{ frac{3}{10} } }{ {a}^{ frac{13}{5} } } = frac{({2^{2} )}^{ frac{3}{10} } }{ sqrt[5]{ {a}^{13} } } = \ \ = frac{ {2}^{ frac{3}{5} } }{ {a}^{2} sqrt[5]{ {a}^{ 3} } } = frac{ sqrt[5]{ {2}^{3} } }{ {a}^{2} sqrt[5]{ {a}^{3} } } = frac{ sqrt[5]{8} }{ {a}^{2} sqrt[5]{ {a}^{3} } }")
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Ответил valenivan
0
Решение задания приложено
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