Question

Упростите $( sqrt{2}+1 )^{ frac{log _{6} log _{6} (sqrt{2}+1)}{log _{6} (sqrt{2}+1)} }$

Answer 1

  
 $(1+sqrt{2} )^ {frac{log_{6}log_{6}(1+sqrt{2})}{log_{6}(sqrt{2}+1)}} =\\ (1+sqrt{2} )^ {log_{1+sqrt{2}}log_{6}(1+sqrt{2})} = log_{6}(1+sqrt{2} )$