Question

Упростите
1) (a+3)²+(a-3)²
2) (4a+b)²-(4a-b)²​

Answer 1

Ответ: Внизу

Объяснение:

(a+3)²+(a-3)²=a^2+6a+9+a^2-6a+9=a^2+a^2+6a-6a+9+9=a^2+a^2+9+9=

=2a^2+18

(4a+b)²-(4a-b)²​=16a^2+8ab+b^2-16a^2+8ab-b^2=16a^2-16a^2+8ab+8ab+b^2-b^2=8ab+8ab+b^2-b^2=16ab

Answer 2

$\displaystyle\bf\\1)\\\\(a+3)^{2} +(a-3)^{2} =a^{2} +6a+9+a^{2} -6a+9=2a^{2} +18\\\\\\2)\\\\(4a+b)^{2} -(4a-b)^{2} =(4a)^{2}+2\cdot 4a\cdot b+b^{2}-\Big[(4a)^{2} -2\cdot 4a\cdot b+b^{2} \Big]=\\\\=16a^{2} +8ab+b^{2} -16a^{2} +8ab-b^{2} =16ab$