Question

упростить выражения..........

Answer 1

Ответ: во вложении

Объяснение:

там же

Answer 2

$1) \frac{c}{\sqrt{c}-10 } - \frac{20\sqrt{c}-100 }{\sqrt{c}-10 } =\frac{c-(20\sqrt{c}-100)}{\sqrt{c}-10 } =\frac{c-20\sqrt{c}+100}{\sqrt{c}-10 }=\frac{(\sqrt{c}-10)(\sqrt{c}-10) }{\sqrt{c}-10 } =\sqrt{c}-10\\\\2) \frac{\sqrt{c}-2 }{3\sqrt{c}+3 }-\frac{3\sqrt{c}-4 }{7\sqrt{c}+7 }= \frac{\sqrt{c}-2 }{3(\sqrt{c}+1) }-\frac{3\sqrt{c}-4 }{7(\sqrt{c}+1) }=\frac{7\sqrt{c}-14-3(3\sqrt{c}-4)}{3(\sqrt{c}+1)*7} =\frac{7\sqrt{c} -14-9\sqrt{c}+12 }{21(\sqrt{c}+1) }=\frac{-2\sqrt{c}-2 }{21(\sqrt{c}+1)} =$$\frac{-2(\sqrt{c}+1) }{21(\sqrt{c}+1) } =-\frac{2}{21}$

$3) \sqrt{\frac{1}{6} }+\sqrt\frac{3}{2} +\sqrt\frac{2}{3} +\sqrt54 = {\frac{1}{\sqrt6} }+\frac{\sqrt3}{\sqrt2} +\frac{\sqrt2}{\sqrt3} +3\sqrt6= \frac{\sqrt6}{6}+\frac{\sqrt6}{2}+\frac{\sqrt6}{3} +3\sqrt6=\frac{\sqrt6+3\sqrt6+2\sqrt6-18\sqrt6}{6}=\frac{-12\sqrt6}{6}=-2\sqrt6$

4) $3\sqrt\frac{1}{15} +6\sqrt{0,6}-\sqrt{60}=3\frac{1}{\sqrt{15}} +6{\frac{\sqrt3}{\sqrt5} } -2\sqrt{15}=\frac{3\sqrt{15}}{15}+\frac{6\sqrt{15} }{5}-\frac{2\sqrt{15} }{1}=\frac{3\sqrt{15} +18\sqrt{15 } -30\sqrt{15} }{15}=\frac{-9\sqrt{15} }{15}=-\frac{3\sqrt{15} }{5}$