Question

Упростить:
А) $2sina+frac{2cosa^{2} }{1+sina}$
Б) $1+sin(pi +a) * cos(a+frac{3pi }{2} )-cosa^{2}$

Answer 1

А)

$2 sin( alpha ) + frac{2 times (1 - sin( alpha {}^{2}) ) }{1 + sin( alpha ) }$

$2 sin( alpha ) + frac{2 times (1 - sin( { alpha } times (1 + sin( alpha ) ) }{1 + sin( alpha ) }$

$2 sin( alpha ) + 2(1 - sin( alpha ) )$

2sin(a)+2-2sin(a)=2

Б)

$1 + sin(pi + alpha ) times cos( + frac{3pi}{2} ) - cos( { alpha }^{2} )$

$1 - sin( alpha ) times sin( alpha ) - cos( alpha )$

$1 - sin( { alpha }^{2} ) - cos( { alpha }^{2} )$

1-1=0