Question

УМОЛЯЮ СРОЧНО!!!!!!!!

Answer 1

Ответ:

Объяснение:

а

$D=-8, x1=\frac{4+\sqrt{-8} }{6}, x2=\frac{4-\sqrt{-8} }{6}$

б

$11x^{2} +12=25x-x^{2} \\12x^{2} -25x+12=0\\D=49, x1=\frac{4}{3}, x2=\frac{3}{4}$

в

$(3-m)^{2} =4m(m-3)-15\\9-6m+m^{2}=4m^{2}-12m-15\\-3m^{2}+6m+24=0\\D=-324, x1=-4, x2=2$

г

$\frac{4y^{2}+3 }{15}-\frac{2y}{5}=\frac{5-2y}{10}-\frac{1}{3}\\\\\frac{2(4y^{2}+3)}{30}-\frac{6*2y}{30}=\frac{3(5-2y)}{30}-\frac{10}{30}\\\\8y^{2}+6-12y=15-6y-10\\8y^{2}-6y+1=0\\D=4, x1=\frac{1}{2}, x2=\frac{1}{4}$