Question

УМОЛЯЮ ПОМОГИТЕ ПОЖАЛУЙСТА
ХЭЛП

Answer 1

$(frac{5x+3y}{5x-3y} -frac{25x^2+9y^2}{25x^2-9y^2} )*(frac{1}{5x} -frac{1}{3y})=\(frac{5x+3y}{5x-3y} -frac{25x^2+9y^2}{(5x-3y)(5x+3y)} )*(frac{3y}{5x3y} -frac{5x}{5x3y})=\(frac{(5x+3y)(5x+3y)}{(5x-3y)(5x+3y)} -frac{25x^2+9y^2}{(5x-3y)(5x+3y)} )*(frac{3y-5x}{15xy})=\(frac{25x^2+30xy+9y^2-25x^2-9y^2}{(5x-3y)(5x+3y)}) *frac{-(5x-3y)}{15xy}=\frac{30xy}{(5x-3y)(5x+3y)} *frac{-(5x-3y)}{15xy}=\\frac{-2}{5x+3y}$