Question

у⁴-у³-16у²+16у=0 решить уравнение

Answer 1

$y^4-y^3-16y^2+16y=0, \ y(y^3-y^2-16y+16)=0, \y( y^2(y-1)-16(y-1))=0, \ y(y-1)(y^2-16)=0, \ y(y-1)(y-4)(y+4)=0, \ left[begin{array}{c}y=0,\y-1=0,\y-4=0,\y+4=0;end{array}right. left[begin{array}{c}y=0,\y=1,\y=4,\y=-4.end{array}right.$