Question

Тригонометрия
Задание 23

Answer 1

$frac{10}{ sqrt{2} } times ctg135 times sin210 times cos225 = frac{10}{ sqrt{2} } times ctg(180 - 45) times sin(180 + 30) times cos(180 + 45) = frac{10}{ sqrt{2} } times ( - ctg45) times ( - sin30) times ( - cos45) = frac{10}{ sqrt{2} } times ( - 1) times ( - frac{1}{2} ) times ( - frac{ sqrt{2} }{2} ) = - frac{5}{2}$