Question

Тригонометрия
2sin^2x+2sinx-√3-√3sinx=0

Answer 1

$2sin^2x+2sin x-sqrt{3} -sqrt{3}sin x=0 \ 2sin x(sin x+1)-sqrt{3} (1+sin x)=0 \ (sin x+1)(2sin x-sqrt{3} )=0$

$left[begin{array}{l} sin x+1=0 \ 2sin x-sqrt{3}=0 end{array}$

$left[begin{array}{l} sin x=-1 \ sin x=dfrac{sqrt{3}}{2} end{array}$

$left[begin{array}{l} x_1=-dfrac{pi}{2}+2pi n, nin Z \ x_2=(-1)^kcdot dfrac{pi}{3}+pi k, kin Z end{array}$

Answer 2

Спасибо, бро тян(братан).

Answer 3

да